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Exponential Distribution Calculator

The distribution of waiting times between random events — probabilities, mean, median and the memoryless property that makes it unique.

If events arrive at a constant average rate λ, the gap between consecutive events is exponentially distributed: P(X > t) = e^(−λt).

Results update as you type
Results
P(wait ≤ t)
39.346934%
P(wait > t)
Rate λ
Mean wait
Median wait
Standard deviation
Density at t
90th percentile of the wait
Reviewed September 2026. Pure mathematics: the result does not depend on where you are. Terminology follows US usage (math, parentheses, decimal point).
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About exponential distribution

How the exponential distribution calculator works

If events arrive at a constant average rate λ, the gap between consecutive events is exponentially distributed: P(X > t) = e^(−λt). The mean wait is 1/λ.

Its defining feature is memorylessness: having waited ten minutes already tells you nothing about how much longer you will wait. It is the only continuous distribution with that property, and it is exactly why the exponential is the wrong model for anything that wears out.

Formula: P(X ≤ t) = 1 − e^(−λt); mean = 1/λ

Worked examples

InputsP(wait ≤ t)Note
Mean 10, wait 539.346934%39.3% chance of a wait under 5
Waiting one mean63.212056%63.2% — always, whatever the rate
The median49.997641%50% — the median is ln2 ÷ λ

Frequently asked questions

What does the exponential distribution model?

The time between independent events happening at a constant average rate — calls to a helpdesk, radioactive decays, arrivals at a queue.

What is the memoryless property?

The chance of waiting another 10 minutes is the same whether you have waited 0 minutes or 100. The exponential is the only continuous distribution with this property.

Does that make it wrong for equipment failure?

For anything that wears out, yes. Memorylessness says a 20-year-old machine is as good as new. The Weibull distribution handles ageing properly.

Why is the median below the mean?

Because the distribution is strongly right-skewed. The median is ln2 ÷ λ, about 69% of the mean.

How does it relate to the Poisson distribution?

Two views of the same process: Poisson counts events in a fixed interval, exponential measures the gaps between them.

Where these figures come from

Last checked: September 2026. Formulas are fixed by mathematics and do not change with tax years or regulations.