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Material Removal Rate Calculator

The volume of material a milling or turning cut removes per minute from the cutting parameters, and the time it takes to remove a given volume — the productivity number behind roughing strategies.

In milling, removal rate is the width of cut × depth of cut × table feed: 20 mm wide, 5 mm deep at 800 mm/min is 80 cm³/min.

Results update as you type
Results
Material removal rate
80 cm³/min
Time to remove that volume
Spindle power needed (approx.)
Per hour
Reviewed September 2026. Operations arithmetic: the same measures in every plant, in your own units. Production targets computed here carry no weight against WHS duties; plant and machinery obligations are set by the model WHS laws.
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About material removal rate

How the material removal rate calculator works

In milling, removal rate is the width of cut × depth of cut × table feed: 20 mm wide, 5 mm deep at 800 mm/min is 80 cm³/min. In turning it is the depth of cut × feed per revolution × surface speed. Higher rates need more spindle power (roughly 1 kW per 30 cm³/min in steel with a sharp tool) and shorter tool life, so the figure is a trade-off, not a target on its own.

Formula: milling: MRR = aₑ × aₚ × v_f; turning: MRR = aₚ × f × v_c × 1,000

Worked examples

InputsMaterial removal rateNote
Milling 20 mm wide, 5 mm deep at 800 mm/min80 cm³/min80 cm³/min; 6.25 min for 500 cm³
Turning 3 mm deep, 0.3 mm/rev at 200 m/min180 cm³/min180 cm³/min
Aluminium roughing: 12 × 10 mm at 5,000 mm/min600 cm³/min600 cm³/min, 9 kW

Frequently asked questions

Why is turning MRR depth × feed × speed?

Each revolution removes a ring of the depth of cut and the feed width, and the surface speed says how much circumference passes per minute: aₚ × f × v_c with v_c in m/min gives cm³/min after the unit conversion.

How do I raise the rate?

In milling, take a wider or deeper cut before feeding faster — chip load per tooth has a ceiling. High-feed and trochoidal strategies raise MRR by using the tool differently, not by pushing the same cut harder.

What limits it?

Spindle power (the power row), rigidity and chatter, tool life, and chip evacuation. Aluminium in a rigid machine can hit 1,000 cm³/min; titanium struggles past 50.

What specific cutting energy should I use?

About 0.015 kW per cm³/min for aluminium, 0.03–0.05 for mild and alloy steels, 0.06 or more for titanium and nickel alloys, less with a sharp tool and more as it wears. It gives the net power at the cut; add 20–30% for drive losses.

Where these figures come from

Last checked: September 2026. Definitions follow standard operations-management practice; where plants commonly differ, the page says so.